When sixty *consecutive odd* integers are added together, their sum is \(4800\).

Determine the largest of the sixty integers.

Note:

In solving the above problem, it may be helpful to use the fact that the sum of the first \(n\) positive integers is equal to \(\dfrac{n(n+1)}{2}\). That is, \[1 + 2 + 3 + … + n = \frac{n(n+1)}{2}\] For example, \(1 + 2 + 3 + 4 + 5 = 15\), and \(\dfrac{5(6)}{2} = 15.\)

Also, \(1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 = 36 \text{, and } \dfrac{8(9)}{2} = 36.\)