# Problem of the Week Problem E Count on That

Let $$n$$ be a positive integer. How many values of $$n$$ satisfy the following inequality? $(n-1)(n-3)(n-5)\cdots(n-2019)(n-2021) \leq 0$ Note: The product on the left side of the inequality consists of $$1011$$ factors of the form $$n-d$$, where the value of $$d$$ starts at $$1$$ and increases by $$2$$ for each subsequent factor.