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Problem of the Week
Problem B and Solution
Work it Out

Problem

A gym is hosting an outdoor group exercise class. For many of the exercises, participants will need to make sure they are spaced well apart.

  1. A large grassy field has dimensions of \(100\) m by \(200\) m. The field was divided into squares that were each \(2\) m by \(2\) m, as shown.

    The rectangular field with a few 2 m by 2 m squares arranged side by side along an edge of the field.

    If one person was in the middle of each square, how many people could be on the field?

  2. Imaginary Park is exactly \(1\) km by \(1\) km, or \(1\) km\(^2\), which is equivalent to \(100\) hectares (ha) in size. If this park was divided into \(2\) m by \(2\) m squares for an exercise class like in part (a), and there is one person in the middle of each square, how many people would be in this park? How many people per hectare is that?
  3. Stanley Park is located in Vancouver, BC. While not a rectangle, it covers an area of \(405\) hectares. Suppose that \(\frac{1}{5}\) of the park is not forested. If the number of people per hectare in the non-forested area of Stanley Park is the same as the number of people per hectare in Imaginary Park in part (b), how many people could do the exercise class in the non-forested area of Stanley Park?

Solution

  1. We need to figure out the number of \(2\) m by \(2\) m squares in the field. Since there are \(200\div 2 =100\) squares along the long side of the park, and \(100\div 2 = 50\) squares along the short side, there are \(100 \times 50 = 5000\) squares in total. That means the field could accommodate \(5000\) people.
  2. Since Imaginary Park is \(1\) km by \(1\) km (or \(1000\) m by \(1000\) m), there could be \(1000\div 2 = 500\) people in each row. Since there are \(1000\div 2 = 500\) such rows, there could be \(500 \times 500=250\,000\) people in \(100\) ha of space. This works out to \(250\,000\div 100 = 2500\) people per ha.
  3. The non-forested area of Stanley Park is \(\frac{1}{5}\) of \(405\) ha, or \(\frac{1}{5}\times 405 = 81\) ha. This area will accommodate \(2500\) people per ha. This means a total of \(2500 \times 81 = 202\,500\) people could be present in the non-forested area of Stanley Park at one time.