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Problem of the Week
Problem B and Solution
Seeking Parts Unknown...

Problem

Sylvana and Roberto divide a \(40\) m by \(75\) m rectangular lot to form two yards, as shown in the diagram below.

The area of Roberto’s yard is \(40\%\) of the total area of the two properties.

  1. What are the values of \(x\) and \(y\), the missing dimensions of Roberto’s yard?

  2. What is the area of each yard?

Solution

  1. From the two sides of the rectangle of length \(75\) m, we must have \(60\text{ m} + x=75\text{ m}\) and \(30\text{ m}+y=75\text{ m}\). Thus, the missing dimensions of Roberto’s yard are \(x=75-60=15\) m and \(y=75-30=45\) m.

  2. The total area of the two yards is \(40\text{\,m}\times 75\text{\,m}=3000\) m\(^2\). The area of each yard can be found in a variety of ways: