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Problem of the Week
Problem B and Solution
Measuring Feet - A Great Feat!

Problem

While reading an article in Teen Feat Magazine, Sundip learned that the mean (average) length of an \(11\)-year-old’s foot is \(22.9\,\)cm. He wondered how many of his \(11\)-year-old friends had “average” feet. Here is the information of the foot lengths, in cm, that he gathered from himself and \(11\) of his friends: \[19.1,~23.3,~21.7, ~24.3, ~22.1,~22.4,~20.7,~21.9,~22.5,~24.1,~26.4,~24.7\]

  1. Complete the frequency table below to reveal the number of students with foot lengths within each interval.

    Foot Length Tally Frequency Relative Frequency
    \(18.0\) - \(19.9\)
    \(20.0\) - \(21.9\)
    \(22.0\) - \(23.9\)
    \(24.0\) - \(25.9\)
    \(26.0\) - \(27.9\)

  2. What is the mean (average) foot length for Sundip and his friends? How does it compare to the average for \(11\)-year-olds?

  3. Does the information in the table reveal any similarities or differences among the students as to foot length?

  4. Sundip’s article also stated that fifty years ago, the average foot length an \(11\)-year-old was about \(21.9\,\)cm. How do his friends’ sizes compare to those of fifty years ago?

Solution

  1. Here is the completed frequency table.

    Foot Length Tally Frequency Relative Frequency
    \(18.0\) - \(19.9\) Tally of 1 \(1\) \(\frac{1}{12} \approx 8.3\%\)
    \(20.0\) - \(21.9\) Tally of 3 \(3\) \(\frac{3}{12} = 25\%\)
    \(22.0\) - \(23.9\) Tally of 4 \(4\) \(\frac{4}{12} \approx 33.3\%\)
    \(24.0\) - \(25.9\) Tally of 3 \(3\) \(\frac{3}{12} = 25\%\)
    \(26.0\) - \(27.9\) Tally of 1 \(1\) \(\frac{1}{12} \approx 8.3\%\)
  2. To find the mean foot length for Sundip and his friends, we add up all the foot lengths and divide by \(12\). The sum of the foot lengths is \(273.2\,\)cm, and so the average is \(\frac{273.2}{12} \approx 22.8\,\)cm. The average for Sundip and his friends is slightly lower than the average of \(22.9\,\)cm for \(11\)-year-olds.

  3. The table reveals that the foot lengths of Sundip and his friends are concentrated in their middle range, with only one person at each end of the possible lengths.

  4. The average foot length of Sundip and his friends is about \(1\) cm longer than the average of \(50\) years ago.