#
Problem
of the Week

Problem
A and Solution

What
Number Am I?

## Problem

I am a \(4\)-digit number.

My ones digit plus my thousands digit is equal to my tens digit plus
my hundreds digit.

My tens digit is twice as much as my thousands digit.

My ones digit is the largest single-digit whole number.

My thousands digit is \(4\).

What number am I?

## Solution

We are given that the ones digit is the largest single-digit whole
number. Since the largest single-digit whole number is \(9\), the ones digit must be a \(9\).

We are also given that the thousands digit is a \(4\). Since the tens digit is twice as much
as the thousands digit, then the tens digit must be \(2 \times 4 = 8\).

Also, the sum of the ones digit and the thousands digit is \(9 + 4 = 13\). Thus, the sum of the hundreds
digit and the tens digit must be \(13\).

Since the tens digit is \(8\), then the
hundreds digit must be \(13 - 8 =
5\).

Thus, the thousands digit is \(4\),
the hundreds digit is \(5\), the tens
digit is \(8\), and the ones digit is
\(9\). Therefore, the number is \(4589\).