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Problem of the Week
Problem C and Solution
Fruit Display

Problem

Jigme placed five oranges in a row on a long plate. He then placed one apple in each of the spaces in the row between two oranges.

Next, he placed one banana in each of the spaces between two fruits already in the row.

He then repeated this procedure with pears, then peaches, and finally with strawberries.

Determine the total number of fruits in the row.

Solution

After placing \(5\) oranges in the row, there are \(4\) spaces between the fruits. So Jigme placed \(4\) apples in the row. At this point, there are \(5+4=9\) fruits in the row.

Since there are now \(9\) fruits in the row, there are \(8\) spaces between the fruits. So Jigme placed \(8\) bananas in the row. At this point, there are \(9+8=17\) fruits in the row.

Since there are now \(17\) fruits in the row, there are \(16\) spaces between the fruits. So Jigme placed \(16\) pears in the row. At this point, there are \(17+16=33\) fruits in the row.

Since there are now \(33\) fruits in the row, there are \(32\) spaces between the fruits. So Jigme placed \(32\) peaches in the row. At this point, there are \(33+32=65\) fruits in the row.

Finally, since there are now \(65\) fruits in the row, there are \(64\) spaces between the fruits. So Jigme placed \(64\) strawberries in the row. At this point, there are \(65+64=129\) fruits in the row.

Thus, there are \(129\) fruits in the row in total.

Extension:

You may have noticed a pattern in the total number of fruits after each new fruit was added. If Jigme placed fruits in this way using \(n\) different fruits, there will be a total of \(2^{n+1}+1\) fruits in the row. Can you see why? Start by looking at the number of spaces between the fruits.